Problems on Ages is one of the very important section of Quantitative Aptitude. Questions from this topic will be asked in all competitive exams.

To make the chapter easy for you all, we are providing you all some basic concept and tricks.

Concepts

1) If the present age of a person is “x” years old

    Then the age 5years hence/after will be= “x+5”

    Then the age 5years before/ago was = “x-5”

2) If A ages after 2 years will be twice the age of B.

         (A+2) = 2 (B+2)

3) If ratio of ages of A:B is 2:3, then in terms of value we can write.

          A = 2x years     &   B = 3x years          

The ratio of ages of father and son is 9 : 4. If the age of son is 28 years, then find the age of father.

a) 63 years                    b) 56 years                    c) 70 years                    d) 49 years

Solution:

Given that, F : S = 9 : 4

Let, F = 9x, S = 4x         (x – common factor)                              Present Ages

S = 4x = 28 years           Þ       x = 7                                       Father – F, Son – S

Father’s age F = 9x = 9 × 7 = 63 years.                            

Shortcut:

F : S = 9 : 4

Son, S = 4 Parts                             28 years

Father, F = 9 Parts                              ?   = (9 × 28) / 4 = 63 years.

Answer: a

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